-0.06h2+2h+4=A(h)

Solution for -0.06h2+2h+4=A(h) equation:

-0.06h^2+2h+4=(h)

We move all terms to the left:

-0.06h^2+2h+4-((h))=0

determiningTheFunctionDomain
-0.06h^2+2h-h+4=0

We add all the numbers together, and all the variables

-0.06h^2+h+4=0

a = -0.06; b = 1; c = +4;
Δ = b2-4ac
Δ = 12-4·(-0.06)·4
Δ = 1.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{1.96}}{2*-0.06}=\frac{-1-\sqrt{1.96}}{-0.12}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{1.96}}{2*-0.06}=\frac{-1+\sqrt{1.96}}{-0.12}
$