-0.08x2+160x-3000=0

Solution for -0.08x2+160x-3000=0 equation:

-0.08x^2+160x-3000=0

a = -0.08; b = 160; c = -3000;
Δ = b2-4ac
Δ = 1602-4·(-0.08)·(-3000)
Δ = 24640
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{24640}=\sqrt{64*385}=\sqrt{64}*\sqrt{385}=8\sqrt{385}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(160)-8\sqrt{385}}{2*-0.08}=\frac{-160-8\sqrt{385}}{-0.16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(160)+8\sqrt{385}}{2*-0.08}=\frac{-160+8\sqrt{385}}{-0.16}
$