-0.1(127)+0.9x=0.5x(x-16)

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Solution for -0.1(127)+0.9x=0.5x(x-16) equation: 



-0.1(127)+0.9x=0.5x(x-16)

We move all terms to the left:

-0.1(127)+0.9x-(0.5x(x-16))=0



We calculate terms in parentheses: -(0.5x(x-16)), so:

0.5x(x-16)

We multiply parentheses

0x^2+0x

We add all the numbers together, and all the variables

x^2+x

Back to the equation:

-(x^2+x)



We get rid of parentheses

-x^2+0.9x-x-0.1127=0

We add all the numbers together, and all the variables

-1x^2-0.1x-0.1127=0

a = -1; b = -0.1; c = -0.1127;
Δ = b2-4ac
Δ = -0.12-4·(-1)·(-0.1127)
Δ = -0.4408
Delta is less than zero, so there is no solution for the equation

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