-0.2(-8+d)=0.3(2d+1)+0.5

Solution for -0.2(-8+d)=0.3(2d+1)+0.5 equation:

-0.2(-8+d)=0.3(2d+1)+0.5

We move all terms to the left:

-0.2(-8+d)-(0.3(2d+1)+0.5)=0

We add all the numbers together, and all the variables

-0.2(d-8)-(0.3(2d+1)+0.5)=0

We multiply parentheses

-0.2d-(0.3(2d+1)+0.5)+1.6=0


We calculate terms in parentheses: -(0.3(2d+1)+0.5), so:

0.3(2d+1)+0.5

We multiply parentheses

0.6d+0.3+0.5

We add all the numbers together, and all the variables

0.6d+0.8

Back to the equation:

-(0.6d+0.8)


We get rid of parentheses

-0.2d-0.6d-0.8+1.6=0

We add all the numbers together, and all the variables

-0.8d+0.8=0

We move all terms containing d to the left, all other terms to the right

-0.8d=-0.8

d=-0.8/-0.8

d=1