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-0.25x^2+1.5=-10.75
We move all terms to the left:
-0.25x^2+1.5-(-10.75)=0
We add all the numbers together, and all the variables
-0.25x^2+12.25=0
a = -0.25; b = 0; c = +12.25;
Δ = b2-4ac
Δ = 02-4·(-0.25)·12.25
Δ = 12.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{12.25}}{2*-0.25}=\frac{0-\sqrt{12.25}}{-0.5} =-\frac{\sqrt{}}{-0.5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{12.25}}{2*-0.25}=\frac{0+\sqrt{12.25}}{-0.5} =\frac{\sqrt{}}{-0.5} $
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