-0.25x2+3x+1=0

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Solution for -0.25x2+3x+1=0 equation:



-0.25x^2+3x+1=0
a = -0.25; b = 3; c = +1;
Δ = b2-4ac
Δ = 32-4·(-0.25)·1
Δ = 10
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{10}}{2*-0.25}=\frac{-3-\sqrt{10}}{-0.5} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{10}}{2*-0.25}=\frac{-3+\sqrt{10}}{-0.5} $

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