-0.2x(3x-8)=1.6+2x

Solution for -0.2x(3x-8)=1.6+2x equation:

-0.2x(3x-8)=1.6+2x

We move all terms to the left:

-0.2x(3x-8)-(1.6+2x)=0

We add all the numbers together, and all the variables

-0.2x(3x-8)-(2x+1.6)=0

We multiply parentheses

-0x^2-0x-(2x+1.6)=0

We get rid of parentheses

-0x^2-0x-2x-1.6=0

We add all the numbers together, and all the variables

-1x^2-3x-1.6=0

a = -1; b = -3; c = -1.6;
Δ = b2-4ac
Δ = -32-4·(-1)·(-1.6)
Δ = 2.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{2.6}}{2*-1}=\frac{3-\sqrt{2.6}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{2.6}}{2*-1}=\frac{3+\sqrt{2.6}}{-2}
$