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-0.5x^2+0.75x-0.1=0
a = -0.5; b = 0.75; c = -0.1;
Δ = b2-4ac
Δ = 0.752-4·(-0.5)·(-0.1)
Δ = 0.3625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.75)-\sqrt{0.3625}}{2*-0.5}=\frac{-0.75-\sqrt{0.3625}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.75)+\sqrt{0.3625}}{2*-0.5}=\frac{-0.75+\sqrt{0.3625}}{-1} $
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