-0.5x2+x-0.5=0

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Solution for -0.5x2+x-0.5=0 equation: 



-0.5x^2+x-0.5=0

a = -0.5; b = 1; c = -0.5;
Δ = b2-4ac
Δ = 12-4·(-0.5)·(-0.5)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-1}{-1}=1$

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