-1(-4z-5)-2=2(2z+5)-6

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Solution for -1(-4z-5)-2=2(2z+5)-6 equation: 



-1(-4z-5)-2=2(2z+5)-6

We move all terms to the left:

-1(-4z-5)-2-(2(2z+5)-6)=0



We calculate terms in parentheses: -(2(2z+5)-6), so:

2(2z+5)-6

We multiply parentheses

4z+10-6

We add all the numbers together, and all the variables

4z+4

Back to the equation:

-(4z+4)



We get rid of parentheses

-1(-4z-5)-4z-4-2=0

We add all the numbers together, and all the variables

-4z-1(-4z-5)-6=0

We move all terms containing z to the left, all other terms to the right

-4z-1(-4z-5)=6

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