-1(c-3)+2c=-(c-5)+4

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Solution for -1(c-3)+2c=-(c-5)+4 equation: 



-1(c-3)+2c=-(c-5)+4

We move all terms to the left:

-1(c-3)+2c-(-(c-5)+4)=0

We add all the numbers together, and all the variables

2c-1(c-3)-(-(c-5)+4)=0



We calculate terms in parentheses: -(-(c-5)+4), so:

-(c-5)+4

We get rid of parentheses

-c+5+4

We add all the numbers together, and all the variables

-1c+9

Back to the equation:

-(-1c+9)



We get rid of parentheses

2c-1(c-3)+1c-9=0

We add all the numbers together, and all the variables

3c-1(c-3)-9=0

We move all terms containing c to the left, all other terms to the right

3c-1(c-3)=9

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