-1(x+3)+6=8(x-2)

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Solution for -1(x+3)+6=8(x-2) equation: 



-1(x+3)+6=8(x-2)

We move all terms to the left:

-1(x+3)+6-(8(x-2))=0



We calculate terms in parentheses: -(8(x-2)), so:

8(x-2)

We multiply parentheses

8x-16

Back to the equation:

-(8x-16)



We get rid of parentheses

-1(x+3)-8x+16+6=0

We add all the numbers together, and all the variables

-8x-1(x+3)+22=0

We move all terms containing x to the left, all other terms to the right

-8x-1(x+3)=-22

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