-1(x-4)-7=3(x+2)

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Solution for -1(x-4)-7=3(x+2) equation: 



-1(x-4)-7=3(x+2)

We move all terms to the left:

-1(x-4)-7-(3(x+2))=0



We calculate terms in parentheses: -(3(x+2)), so:

3(x+2)

We multiply parentheses

3x+6

Back to the equation:

-(3x+6)



We get rid of parentheses

-1(x-4)-3x-6-7=0

We add all the numbers together, and all the variables

-3x-1(x-4)-13=0

We move all terms containing x to the left, all other terms to the right

-3x-1(x-4)=13

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