-1-2(2-4v)=4(v+1)+3

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Solution for -1-2(2-4v)=4(v+1)+3 equation: 



-1-2(2-4v)=4(v+1)+3

We move all terms to the left:

-1-2(2-4v)-(4(v+1)+3)=0

We add all the numbers together, and all the variables

-2(-4v+2)-(4(v+1)+3)-1=0

We multiply parentheses

8v-(4(v+1)+3)-4-1=0



We calculate terms in parentheses: -(4(v+1)+3), so:

4(v+1)+3

We multiply parentheses

4v+4+3

We add all the numbers together, and all the variables

4v+7

Back to the equation:

-(4v+7)



We add all the numbers together, and all the variables

8v-(4v+7)-5=0

We get rid of parentheses

8v-4v-7-5=0

We add all the numbers together, and all the variables

4v-12=0

We move all terms containing v to the left, all other terms to the right

4v=12

v=12/4

v=3

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