-1.6=-2/t2

Solution for -1.6=-2/t2 equation:

-1.6=-2/t2

We move all terms to the left:

-1.6-(-2/t2)=0


Domain of the equation: t2)!=0

t!=0/1

t!=0

t∈R


We get rid of parentheses

2/t2-1.6=0

We multiply all the terms by the denominator


-(1.6)*t2+2=0

We multiply parentheses

-1.6t^2+2=0

a = -1.6; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·(-1.6)·2
Δ = 12.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{12.8}}{2*-1.6}=\frac{0-\sqrt{12.8}}{-3.2}
=-\frac{\sqrt{}}{-3.2}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{12.8}}{2*-1.6}=\frac{0+\sqrt{12.8}}{-3.2}
=\frac{\sqrt{}}{-3.2}
$