-1/(2y-1)

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Solution for -1/(2y-1) equation: 


D( y )

2*y-1 = 0

2*y-1 = 0

2*y-1 = 0

2*y-1 = 0 // + 1

2*y = 1 // : 2

y = 1/2

y in (-oo:1/2) U (1/2:+oo)

-1/(2*y-1) = 0

y belongs to the empty set

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