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-1/(x+2)=-2/5x
We move all terms to the left:
-1/(x+2)-(-2/5x)=0
Domain of the equation: (x+2)!=0
We move all terms containing x to the left, all other terms to the right
x!=-2
x∈R
Domain of the equation: 5x)!=0We get rid of parentheses
x!=0/1
x!=0
x∈R
-1/(x+2)+2/5x=0
We calculate fractions
(-5x)/(5x^2+10x)+(2x+4)/(5x^2+10x)=0
We multiply all the terms by the denominator
(-5x)+(2x+4)=0
We get rid of parentheses
-5x+2x+4=0
We add all the numbers together, and all the variables
-3x+4=0
We move all terms containing x to the left, all other terms to the right
-3x=-4
x=-4/-3
x=1+1/3
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