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-1/10(x-1)-1=3/2(x+2)
We move all terms to the left:
-1/10(x-1)-1-(3/2(x+2))=0
Domain of the equation: 10(x-1)!=0
x∈R
Domain of the equation: 2(x+2))!=0We calculate fractions
x∈R
(-2xx/(10(x-1)*2(x+2)))+(-30xx/(10(x-1)*2(x+2)))-1=0
We calculate terms in parentheses: +(-2xx/(10(x-1)*2(x+2))), so:
-2xx/(10(x-1)*2(x+2))
We multiply all the terms by the denominator
-2xx
Back to the equation:
+(-2xx)
We calculate terms in parentheses: +(-30xx/(10(x-1)*2(x+2))), so:We get rid of parentheses
-30xx/(10(x-1)*2(x+2))
We multiply all the terms by the denominator
-30xx
Back to the equation:
+(-30xx)
-2xx-30xx-1=0
We move all terms containing x to the left, all other terms to the right
-2xx-30xx=1
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