-1/10(x-20)1/2(x+2)=x+9

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Solution for -1/10(x-20)1/2(x+2)=x+9 equation: 


x in (-oo:+oo)

(((-1/10)*(x-20)^1)/2)*(x+2) = x+9 // - x+9

(((-1/10)*(x-20)^1)/2)*(x+2)-x-9 = 0

(((-1/10)*(x-20))/2)*(x+2)-x-9 = 0

(-1/10*(x-20)*(x+2))/2-x-9 = 0

(-1/10*(x-20)*(x+2))/2+(2*(-x))/2+(-9*2)/2 = 0

2*(-x)-1/10*(x-20)*(x+2)-9*2 = 0

4-1/10*x^2-1/5*x-18 = 0

-1/10*x^2-1/5*x-14 = 0

-1/10*x^2-1/5*x-14 = 0

-1*(1/10*x^2+1/5*x+14) = 0

1/10*x^2+1/5*x+14 = 0

DELTA = (1/5)^2-(1/10*4*14)

DELTA = -139/25

DELTA < 0

-1 = 0

-1/2 = 0

-1/2 = 0 // * 2

-1 = 0

x belongs to the empty set

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