-1/12(4n-3)=1/4(2n+1)

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Solution for -1/12(4n-3)=1/4(2n+1) equation: 



-1/12(4n-3)=1/4(2n+1)

We move all terms to the left:

-1/12(4n-3)-(1/4(2n+1))=0



Domain of the equation: 12(4n-3)!=0

n∈R





Domain of the equation: 4(2n+1))!=0

n∈R



We calculate fractions


(-4n2/(12(4n-3)*4(2n+1)))+(-12n4/(12(4n-3)*4(2n+1)))=0



We calculate terms in parentheses: +(-4n2/(12(4n-3)*4(2n+1))), so:

-4n2/(12(4n-3)*4(2n+1))

We multiply all the terms by the denominator


-4n2

We add all the numbers together, and all the variables

-4n^2

Back to the equation:

+(-4n^2)





We calculate terms in parentheses: +(-12n4/(12(4n-3)*4(2n+1))), so:

-12n4/(12(4n-3)*4(2n+1))

We multiply all the terms by the denominator


-12n4

We add all the numbers together, and all the variables

-12n^4

We do not support enpression: n^4

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