-1/2(10x-8)+6=48-x-2

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Solution for -1/2(10x-8)+6=48-x-2 equation: 



-1/2(10x-8)+6=48-x-2

We move all terms to the left:

-1/2(10x-8)+6-(48-x-2)=0



Domain of the equation: 2(10x-8)!=0

x∈R



We add all the numbers together, and all the variables

-1/2(10x-8)-(-1x+46)+6=0

We get rid of parentheses

-1/2(10x-8)+1x-46+6=0

We multiply all the terms by the denominator


1x*2(10x-8)-46*2(10x-8)+6*2(10x-8)-1=0

Wy multiply elements

2x^2(1-92x(1+12x(1-1=0

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