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(-1/2)*(12*x-(20*y)) = 0
(-1/2)*(12*x-20*y) = 0
-1/2*(12*x-20*y) = 0
( -1/2 )
-1/2 = 0
x belongs to the empty set
( 12*x-20*y )
12*x-20*y = 0 // + -20*y
12*x = -(-20*y) // : 12
x = (-(-20*y))/12
x = (5*y)/3
x = (5*y)/3
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