-1/2(16x-4)+2x=6(x-4)+13(2)

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Solution for -1/2(16x-4)+2x=6(x-4)+13(2) equation: 



-1/2(16x-4)+2x=6(x-4)+13(2)

We move all terms to the left:

-1/2(16x-4)+2x-(6(x-4)+13(2))=0



Domain of the equation: 2(16x-4)!=0

x∈R



We add all the numbers together, and all the variables

2x-1/2(16x-4)-(6(x-4)+132)=0

We multiply all the terms by the denominator


2x*2(16x-4)-((6(x-4)+132))*2(16x-4)-1=0



We calculate terms in parentheses: -((6(x-4)+132))*2(16x-4), so:

(6(x-4)+132))*2(16x-4



Wy multiply elements

4x^2(1-((6(x-4)+132))*2(16x-4)-1=0

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