-1/2(3x+2)=3(-x-6)/2

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Solution for -1/2(3x+2)=3(-x-6)/2 equation: 


x in (-oo:+oo)

(-1/2)*(3*x+2) = (3*(-x-6))/2 // - (3*(-x-6))/2

(-1/2)*(3*x+2)-((3*(-x-6))/2) = 0

(-1/2)*(3*x+2)+(-3/2)*(-x-6) = 0

-1/2*(3*x+2)-3/2*(-x-6) = 0

-1/2*(3*x+2)-3/2*(-x-6) = 0

8 = 0

8 = 0

x belongs to the empty set

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