-1/2(3x+4)=16

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Solution for -1/2(3x+4)=16 equation: 



-1/2(3x+4)=16

We move all terms to the left:

-1/2(3x+4)-(16)=0



Domain of the equation: 2(3x+4)!=0

x∈R



We multiply all the terms by the denominator


-16*2(3x+4)-1=0

Wy multiply elements

-32x(3-1=0

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