-1/2(4a+4)=1/3(12a-6)

Solution for -1/2(4a+4)=1/3(12a-6) equation:

-1/2(4a+4)=1/3(12a-6)

We move all terms to the left:

-1/2(4a+4)-(1/3(12a-6))=0


Domain of the equation: 2(4a+4)!=0

a∈R



Domain of the equation: 3(12a-6))!=0

a∈R


We calculate fractions


(-3a1/(2(4a+4)*3(12a-6)))+(-2a4/(2(4a+4)*3(12a-6)))=0


We calculate terms in parentheses: +(-3a1/(2(4a+4)*3(12a-6))), so:

-3a1/(2(4a+4)*3(12a-6))

We multiply all the terms by the denominator


-3a1

We add all the numbers together, and all the variables

-3a

Back to the equation:

+(-3a)



We calculate terms in parentheses: +(-2a4/(2(4a+4)*3(12a-6))), so:

-2a4/(2(4a+4)*3(12a-6))

We multiply all the terms by the denominator


-2a4

We add all the numbers together, and all the variables

-2a^4

We do not support eapression: a^4