-1/2(7z+4)+1/2((5z-15)=0

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Solution for -1/2(7z+4)+1/2((5z-15)=0 equation: 



-1/2(7z+4)+1/2((5z-15)=0



Domain of the equation: 2(7z+4)!=0

z∈R





Domain of the equation: 2((5z-15)!=0

z∈R



We calculate fractions


(-2z(()/(2(7z+4)*2((5z-15))+(2z7/(2(7z+4)*2((5z-15))=0



We calculate terms in parentheses: +(-2z(()/(2(7z+4)*2((5z-15))+(2z7/(2(7z+4)*2((5z-15)), so:

-2z(()/(2(7z+4)*2((5z-15))+(2z7/(2(7z+4)*2((5z-15)

We can not solve this equation

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