-1/2(7z+4)=1/5(5z-15)

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Solution for -1/2(7z+4)=1/5(5z-15) equation: 



-1/2(7z+4)=1/5(5z-15)

We move all terms to the left:

-1/2(7z+4)-(1/5(5z-15))=0



Domain of the equation: 2(7z+4)!=0

z∈R





Domain of the equation: 5(5z-15))!=0

z∈R



We calculate fractions


(-5z5/(2(7z+4)*5(5z-15)))+(-2z7/(2(7z+4)*5(5z-15)))=0



We calculate terms in parentheses: +(-5z5/(2(7z+4)*5(5z-15))), so:

-5z5/(2(7z+4)*5(5z-15))

We multiply all the terms by the denominator


-5z5

We add all the numbers together, and all the variables

-5z^5

We do not support ezpression: z^5

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