-1/2(b+2)+3b=1

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Solution for -1/2(b+2)+3b=1 equation: 



-1/2(b+2)+3b=1

We move all terms to the left:

-1/2(b+2)+3b-(1)=0



Domain of the equation: 2(b+2)!=0

b∈R



We add all the numbers together, and all the variables

3b-1/2(b+2)-1=0

We multiply all the terms by the denominator


3b*2(b+2)-1*2(b+2)-1=0

Wy multiply elements

6b^2(b-2b(b-1=0

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