-1/2(b+2)=-1-3b

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Solution for -1/2(b+2)=-1-3b equation: 



-1/2(b+2)=-1-3b

We move all terms to the left:

-1/2(b+2)-(-1-3b)=0



Domain of the equation: 2(b+2)!=0

b∈R



We add all the numbers together, and all the variables

-1/2(b+2)-(-3b-1)=0

We get rid of parentheses

-1/2(b+2)+3b+1=0

We multiply all the terms by the denominator


3b*2(b+2)+1*2(b+2)-1=0

Wy multiply elements

6b^2(b+2b(b-1=0

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