-1/2(g+2)=-3-g

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Solution for -1/2(g+2)=-3-g equation: 



-1/2(g+2)=-3-g

We move all terms to the left:

-1/2(g+2)-(-3-g)=0



Domain of the equation: 2(g+2)!=0

g∈R



We add all the numbers together, and all the variables

-1/2(g+2)-(-1g-3)=0

We get rid of parentheses

-1/2(g+2)+1g+3=0

We multiply all the terms by the denominator


1g*2(g+2)+3*2(g+2)-1=0

Wy multiply elements

2g^2(g+6g(g-1=0

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