-1/2(s-6)-4=-1/2(1+s)

Solution for -1/2(s-6)-4=-1/2(1+s) equation:

-1/2(s-6)-4=-1/2(1+s)

We move all terms to the left:

-1/2(s-6)-4-(-1/2(1+s))=0


Domain of the equation: 2(s-6)!=0

s∈R



Domain of the equation: 2(1+s))!=0

s∈R


We add all the numbers together, and all the variables

-1/2(s-6)-(-1/2(s+1))-4=0

We calculate fractions


(-2ss/(2(s-6)*2(s+1)))+(-(-2ss)/(2(s-6)*2(s+1)))-4=0


We calculate terms in parentheses: +(-2ss/(2(s-6)*2(s+1))), so:

-2ss/(2(s-6)*2(s+1))

We multiply all the terms by the denominator


-2ss

Back to the equation:

+(-2ss)



We calculate terms in parentheses: +(-(-2ss)/(2(s-6)*2(s+1))), so:

-(-2ss)/(2(s-6)*2(s+1))

We multiply all the terms by the denominator


-(-2ss)

We get rid of parentheses

2ss

Back to the equation:

+(2ss)


We get rid of parentheses

-2ss+2ss-4=0

We move all terms containing s to the left, all other terms to the right

-2ss+2ss=4