-1/2(t+9)+23/4t=8t

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Solution for -1/2(t+9)+23/4t=8t equation: 



-1/2(t+9)+23/4t=8t

We move all terms to the left:

-1/2(t+9)+23/4t-(8t)=0



Domain of the equation: 2(t+9)!=0

t∈R





Domain of the equation: 4t!=0

t!=0/4

t!=0

t∈R



We add all the numbers together, and all the variables

-8t-1/2(t+9)+23/4t=0

We calculate fractions


-8t+(-4t)/(8t^2+72t)+(46tt/(8t^2+72t)=0



We calculate terms in parentheses: +(46tt/(8t^2+72t), so:

46tt/(8t^2+72t

We multiply all the terms by the denominator


46tt

Back to the equation:

+(46tt)



We multiply all the terms by the denominator


-8t*(8t^2+72t)+(-4t)+46tt*(8t^2+72t)=0

We multiply parentheses

-64t^3-576t^2+368t^3+3312t^2+(-4t)=0

We get rid of parentheses

-64t^3-576t^2+368t^3+3312t^2-4t=0

We do not support etpression: t^3

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