-1/2(x2+3x-18)=1x+9

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Solution for -1/2(x2+3x-18)=1x+9 equation: 



-1/2(x2+3x-18)=1x+9

We move all terms to the left:

-1/2(x2+3x-18)-(1x+9)=0



Domain of the equation: 2(x2+3x-18)!=0

x∈R



We add all the numbers together, and all the variables

-1/2(+x^2+3x-18)-(x+9)=0

We get rid of parentheses

-1/2(+x^2+3x-18)-x-9=0

We multiply all the terms by the denominator


-x*2(+x^2+3x-18)-9*2(+x^2+3x-18)-1=0

Wy multiply elements

-2x^2(+-18x(+-1=0

We use the square of the difference formula

-2x^2(-18x(-1=0

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