-1/2+3(y+2)=12

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Solution for -1/2+3(y+2)=12 equation: 


y in (-oo:+oo)

3*(y+2)-1/2 = 12 // - 12

3*(y+2)-1/2-12 = 0

(2*3*(y+2))/2-1/2+(-12*2)/2 = 0

2*3*(y+2)-12*2-1 = 0

6*y-24+11 = 0

6*y-13 = 0

(6*y-13)/2 = 0

(6*y-13)/2 = 0 // * 2

6*y-13 = 0

6*y-13 = 0 // + 13

6*y = 13 // : 6

y = 13/6

y = 13/6

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