-1/2b+3=5

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Solution for -1/2b+3=5 equation: 



-1/2b+3=5

We move all terms to the left:

-1/2b+3-(5)=0



Domain of the equation: 2b!=0

b!=0/2

b!=0

b∈R



We add all the numbers together, and all the variables

-1/2b-2=0

We multiply all the terms by the denominator


-2*2b-1=0

Wy multiply elements

-4b-1=0

We move all terms containing b to the left, all other terms to the right

-4b=1

b=1/-4

b=-1/4

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