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-1/2x+1/2=1/2(3-x)
We move all terms to the left:
-1/2x+1/2-(1/2(3-x))=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 2(3-x))!=0We add all the numbers together, and all the variables
x∈R
-1/2x-(1/2(-1x+3))+1/2=0
We calculate fractions
(-2x(-)/(8x^2(-)+(-(1*2x)/(8x^2(-)=0
We calculate terms in parentheses: +(-2x(-)/(8x^2(-)+(-(1*2x)/(8x^2(-), so:
-2x(-)/(8x^2(-)+(-(1*2x)/(8x^2(-
We can not solve this equation
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