-1/2x+2-4x+5+3/2x=

Solution for -1/2x+2-4x+5+3/2x= equation:

-1/2x+2-4x+5+3/2x=

We move all terms to the left:

-1/2x+2-4x+5+3/2x-()=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R


We add all the numbers together, and all the variables

-4x-1/2x+3/2x=0

We multiply all the terms by the denominator


-4x*2x-1+3=0

We add all the numbers together, and all the variables

-4x*2x+2=0

Wy multiply elements

-8x^2+2=0

a = -8; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·(-8)·2
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8}{2*-8}=\frac{-8}{-16}
=1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8}{2*-8}=\frac{8}{-16}
=-1/2
$