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-1/2x+2/5x=4
We move all terms to the left:
-1/2x+2/5x-(4)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 5x!=0We calculate fractions
x!=0/5
x!=0
x∈R
(-5x)/10x^2+4x/10x^2-4=0
We multiply all the terms by the denominator
(-5x)+4x-4*10x^2=0
We add all the numbers together, and all the variables
4x+(-5x)-4*10x^2=0
Wy multiply elements
-40x^2+4x+(-5x)=0
We get rid of parentheses
-40x^2+4x-5x=0
We add all the numbers together, and all the variables
-40x^2-1x=0
a = -40; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·(-40)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*-40}=\frac{0}{-80} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*-40}=\frac{2}{-80} =-1/40 $
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