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-1/2x+4=-x-3
We move all terms to the left:
-1/2x+4-(-x-3)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
-1/2x-(-1x-3)+4=0
We get rid of parentheses
-1/2x+1x+3+4=0
We multiply all the terms by the denominator
1x*2x+3*2x+4*2x-1=0
Wy multiply elements
2x^2+6x+8x-1=0
We add all the numbers together, and all the variables
2x^2+14x-1=0
a = 2; b = 14; c = -1;
Δ = b2-4ac
Δ = 142-4·2·(-1)
Δ = 204
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{204}=\sqrt{4*51}=\sqrt{4}*\sqrt{51}=2\sqrt{51}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{51}}{2*2}=\frac{-14-2\sqrt{51}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{51}}{2*2}=\frac{-14+2\sqrt{51}}{4} $
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