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-1/2x+4=3x-24
We move all terms to the left:
-1/2x+4-(3x-24)=0
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
-1/2x-3x+24+4=0
We multiply all the terms by the denominator
-3x*2x+24*2x+4*2x-1=0
Wy multiply elements
-6x^2+48x+8x-1=0
We add all the numbers together, and all the variables
-6x^2+56x-1=0
a = -6; b = 56; c = -1;
Δ = b2-4ac
Δ = 562-4·(-6)·(-1)
Δ = 3112
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3112}=\sqrt{4*778}=\sqrt{4}*\sqrt{778}=2\sqrt{778}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-2\sqrt{778}}{2*-6}=\frac{-56-2\sqrt{778}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+2\sqrt{778}}{2*-6}=\frac{-56+2\sqrt{778}}{-12} $
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