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-1/2x+5.5=-x
We move all terms to the left:
-1/2x+5.5-(-x)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
-1/2x-(-1x)+5.5=0
We get rid of parentheses
-1/2x+1x+5.5=0
We multiply all the terms by the denominator
1x*2x+(5.5)*2x-1=0
We multiply parentheses
1x*2x+11x-1=0
Wy multiply elements
2x^2+11x-1=0
a = 2; b = 11; c = -1;
Δ = b2-4ac
Δ = 112-4·2·(-1)
Δ = 129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{129}}{2*2}=\frac{-11-\sqrt{129}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{129}}{2*2}=\frac{-11+\sqrt{129}}{4} $
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