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-1/2x+5=-4x+12
We move all terms to the left:
-1/2x+5-(-4x+12)=0
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
-1/2x+4x-12+5=0
We multiply all the terms by the denominator
4x*2x-12*2x+5*2x-1=0
Wy multiply elements
8x^2-24x+10x-1=0
We add all the numbers together, and all the variables
8x^2-14x-1=0
a = 8; b = -14; c = -1;
Δ = b2-4ac
Δ = -142-4·8·(-1)
Δ = 228
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{228}=\sqrt{4*57}=\sqrt{4}*\sqrt{57}=2\sqrt{57}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2\sqrt{57}}{2*8}=\frac{14-2\sqrt{57}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2\sqrt{57}}{2*8}=\frac{14+2\sqrt{57}}{16} $
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