-1/2x+6x+2=20

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Solution for -1/2x+6x+2=20 equation:



-1/2x+6x+2=20
We move all terms to the left:
-1/2x+6x+2-(20)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
We add all the numbers together, and all the variables
6x-1/2x-18=0
We multiply all the terms by the denominator
6x*2x-18*2x-1=0
Wy multiply elements
12x^2-36x-1=0
a = 12; b = -36; c = -1;
Δ = b2-4ac
Δ = -362-4·12·(-1)
Δ = 1344
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{1344}=\sqrt{64*21}=\sqrt{64}*\sqrt{21}=8\sqrt{21}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-8\sqrt{21}}{2*12}=\frac{36-8\sqrt{21}}{24} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+8\sqrt{21}}{2*12}=\frac{36+8\sqrt{21}}{24} $

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