-1/2x+8=1/4x+16

Solution for -1/2x+8=1/4x+16 equation:

-1/2x+8=1/4x+16

We move all terms to the left:

-1/2x+8-(1/4x+16)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: 4x+16)!=0

x∈R


We get rid of parentheses

-1/2x-1/4x-16+8=0

We calculate fractions


(-4x)/8x^2+(-2x)/8x^2-16+8=0

We add all the numbers together, and all the variables

(-4x)/8x^2+(-2x)/8x^2-8=0

We multiply all the terms by the denominator


(-4x)+(-2x)-8*8x^2=0

Wy multiply elements

-64x^2+(-4x)+(-2x)=0

We get rid of parentheses

-64x^2-4x-2x=0

We add all the numbers together, and all the variables

-64x^2-6x=0

a = -64; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·(-64)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*-64}=\frac{0}{-128}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*-64}=\frac{12}{-128}
=-3/32
$