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-1/2x-(1/2x+4)+12=17x-(3x+5/6)
We move all terms to the left:
-1/2x-(1/2x+4)+12-(17x-(3x+5/6))=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 2x+4)!=0We add all the numbers together, and all the variables
x∈R
-1/2x-(1/2x+4)-(17x-(+3x+5/6))+12=0
We get rid of parentheses
-1/2x-1/2x-(17x-(+3x+5/6))-4+12=0
We calculate fractions
()/12x^2+(-(17x-(+3x+5*2x)/12x^2-4+12=0
We calculate fractions
We do not support expression: x^4
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