-1/2x-(1/2x+4)+12=17x-6(3x+5/5)

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Solution for -1/2x-(1/2x+4)+12=17x-6(3x+5/5) equation: 



-1/2x-(1/2x+4)+12=17x-6(3x+5/5)

We move all terms to the left:

-1/2x-(1/2x+4)+12-(17x-6(3x+5/5))=0



Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R





Domain of the equation: 2x+4)!=0

x∈R



We add all the numbers together, and all the variables

-1/2x-(1/2x+4)-(17x-6(3x+1))+12=0

We get rid of parentheses

-1/2x-1/2x-(17x-6(3x+1))-4+12=0

We multiply all the terms by the denominator


-((17x-6(3x+1)))*2x-4*2x+12*2x-1-1=0

We add all the numbers together, and all the variables

-((17x-6(3x+1)))*2x-4*2x+12*2x-2=0

Wy multiply elements

-((17x-6(3x+1)))*2x-8x+24x-2=0

We add all the numbers together, and all the variables

16x-((17x-6(3x+1)))*2x-2=0

We move all terms containing x to the left, all other terms to the right

16x-((17x-6(3x+1)))*2x=2

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