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-1/2x=2x-6
We move all terms to the left:
-1/2x-(2x-6)=0
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
-1/2x-2x+6=0
We multiply all the terms by the denominator
-2x*2x+6*2x-1=0
Wy multiply elements
-4x^2+12x-1=0
a = -4; b = 12; c = -1;
Δ = b2-4ac
Δ = 122-4·(-4)·(-1)
Δ = 128
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{128}=\sqrt{64*2}=\sqrt{64}*\sqrt{2}=8\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-8\sqrt{2}}{2*-4}=\frac{-12-8\sqrt{2}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+8\sqrt{2}}{2*-4}=\frac{-12+8\sqrt{2}}{-8} $
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