-1/2y+3(y+2)=12

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Solution for -1/2y+3(y+2)=12 equation: 


y in (-oo:+oo)

3*(y+2)+(-1/2)*y = 12 // - 12

3*(y+2)+(-1/2)*y-12 = 0

3*(y+2)-y/2-12 = 0

(2*3*(y+2))/2-y/2+(-12*2)/2 = 0

2*3*(y+2)-y-12*2 = 0

5*y-24+12 = 0

5*y-12 = 0

(5*y-12)/2 = 0

(5*y-12)/2 = 0 // * 2

5*y-12 = 0

5*y-12 = 0 // + 12

5*y = 12 // : 5

y = 12/5

y = 12/5

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