-1/3(-n+5)=2

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Solution for -1/3(-n+5)=2 equation: 



-1/3(-n+5)=2

We move all terms to the left:

-1/3(-n+5)-(2)=0



Domain of the equation: 3(-n+5)!=0

n∈R



We add all the numbers together, and all the variables

-1/3(-1n+5)-2=0

We multiply all the terms by the denominator


-2*3(-1n+5)-1=0

Wy multiply elements

-6n(--1=0

We use the square of the difference formula

-6n(+1=0

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